setRange method
override
Writes some elements of iterable
into a range of this list.
Copies the objects of iterable
, skipping skipCount
objects first,
into the range from start
, inclusive, to end
, exclusive, of this list.
final list1 = <int>[1, 2, 3, 4];
final list2 = <int>[5, 6, 7, 8, 9];
// Copies the 4th and 5th items in list2 as the 2nd and 3rd items
// of list1.
const skipCount = 3;
list1.setRange(1, 3, list2, skipCount);
print(list1); // [1, 8, 9, 4]
The provided range, given by start
and end
, must be valid.
A range from start
to end
is valid if 0 ≤ start
≤ end
≤ length.
An empty range (with end == start
) is valid.
The iterable
must have enough objects to fill the range from start
to end
after skipping skipCount
objects.
If iterable
is this list, the operation correctly copies the elements
originally in the range from skipCount
to skipCount + (end - start)
to
the range start
to end
, even if the two ranges overlap.
If iterable
depends on this list in some other way, no guarantees are
made.
Implementation
void setRange(int start, int end, Iterable<E> iterable, [int skipCount = 0]) {
throw new UnsupportedError("Cannot setRange on immutable List.");
}