round abstract method Null safety

int round()

override

Returns the integer closest to this number.

Rounds away from zero when there is no closest integer: (3.5).round() == 4 and (-3.5).round() == -4.

Throws an UnsupportedError if this number is not finite (NaN or an infinity).

print(3.0.round()); // 3
print(3.25.round()); // 3
print(3.5.round()); // 4
print(3.75.round()); // 4
print((-3.5).round()); // -4

Implementation

int round();