lastIndexWhere method

int lastIndexWhere(
  1. bool test(
    1. E element
    ),
  2. [int? start]
)
override

The last index in the list that satisfies the provided test.

Searches the list from index start to 0. The first time an object o is encountered so that test(o) is true, the index of o is returned. If start is omitted, it defaults to the length of the list.

final notes = <String>['do', 're', 'mi', 're'];
final first = notes.lastIndexWhere((note) => note.startsWith('r')); // 3
final second = notes.lastIndexWhere((note) => note.startsWith('r'),
    2); // 1

Returns -1 if element is not found.

final notes = <String>['do', 're', 'mi', 're'];
final index = notes.lastIndexWhere((note) => note.startsWith('k'));
print(index); // -1

Implementation

int lastIndexWhere(bool test(E element), [int? start]) {
  if (start == null || start >= this.length) start = this.length - 1;

  // TODO(38493): The previous line should promote.
  if (start == null) throw "!";

  for (int i = start; i >= 0; i--) {
    if (test(this[i])) return i;
  }
  return -1;
}