tryParse static method
Parses source
as a, possibly signed, integer literal and returns its
value.
As parse except that this method returns null
if the input is not
valid
Examples:
print(BigInt.tryParse('-12345678901234567890')); // -12345678901234567890
print(BigInt.tryParse('0xFF')); // 255
print(BigInt.tryParse('0xffffffffffffffff')); // 18446744073709551615
// From binary (base 2) value.
print(BigInt.tryParse('1100', radix: 2)); // 12
print(BigInt.tryParse('00011111', radix: 2)); // 31
print(BigInt.tryParse('011111100101', radix: 2)); // 2021
// From octal (base 8) value.
print(BigInt.tryParse('14', radix: 8)); // 12
print(BigInt.tryParse('37', radix: 8)); // 31
print(BigInt.tryParse('3745', radix: 8)); // 2021
// From hexadecimal (base 16) value.
print(BigInt.tryParse('c', radix: 16)); // 12
print(BigInt.tryParse('1f', radix: 16)); // 31
print(BigInt.tryParse('7e5', radix: 16)); // 2021
// From base 35 value.
print(BigInt.tryParse('y1', radix: 35)); // 1191 == 34 * 35 + 1
print(BigInt.tryParse('z1', radix: 35)); // null
// From base 36 value.
print(BigInt.tryParse('y1', radix: 36)); // 1225 == 34 * 36 + 1
print(BigInt.tryParse('z1', radix: 36)); // 1261 == 35 * 36 + 1
Implementation
external static BigInt? tryParse(String source, {int? radix});